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dzema_kg
post Nov 27 2007, 09:07 AM
Post #1





Group: Članovi
Joined: 5-November 07
Member No.: 745
Status: Van MGa
Ime i prezime: nikola adzemovic
Škola/Razred: 1 kragujevacka gimnazija 1SM



molim vas pomagajte na bloku sam
ako se na polju a,b nalazi top a na polju (x,y) pesak ispitati da li top moze da pojede pesaka
pls pomagajte

This post has been edited by dzema_kg: Nov 27 2007, 09:10 AM
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plavusa(i dalje)
post Nov 27 2007, 09:28 AM
Post #2





Group: Članovi
Joined: 11-June 07
From: bas ovde
Member No.: 531
Status: Van MGa
Škola/Razred: mg IVb



poslala sam ti PM kao odgovor
ehhh, cak i ja sam znala zadatak smile.gif


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ja sam plavusa, a koji je tvoj izgovor;)
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Gaara
post Nov 27 2007, 09:30 AM
Post #3





Group: Članovi
Joined: 24-October 06
Member No.: 164
Status: Učenik MGa



Pa ovo i ja znam...
Mislim mozda...
Samo postavis uslov
if (x=a) or (y=b ) then writeln('moze')
else writeln('ne moze')

jel si ovako uradila?

This post has been edited by Yu-gi: Nov 27 2007, 09:30 AM
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dzema_kg
post Nov 27 2007, 09:41 AM
Post #4





Group: Članovi
Joined: 5-November 07
Member No.: 745
Status: Van MGa
Ime i prezime: nikola adzemovic
Škola/Razred: 1 kragujevacka gimnazija 1SM



da hvala ti puno
ako mozes vidi i ovaj pls
z=(m*5*n*n(x,y)+3)/ (max(x*x,y*y)+4)
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Pera Detlic
post Nov 27 2007, 10:31 AM
Post #5





Group: Članovi
Joined: 14-February 07
From: D plejs ver aj liv
Member No.: 442
Status: Učenik MGa
Škola/Razred: MG/IVc



Ako se radi samo sa pozitivnim brojevima i ako je n(x,y) ustvari min(x,y)
IF x>y Then z=(m*5*n*y+3)/ (x*x+4)
ELSE z=(m*5*n*n*x+3)/ (y*y+4)


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Pritisni Alt+F4 za IQ test

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