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Stefan_chemist
post Dec 7 2007, 06:47 PM
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Evo jedan koji se meni posebno svidja...

Pretpostavimo da je a = b.

Onda je a ^ 2 = ab

Ako dodamo -b^2 obema stranama dobijamo

a^2 - b^2 = ab - b^2

Rastavljanjem na cinioce...

( a + b ) (a - b ) = b ( a - b )

Delimo obe strane sa ( a - b )

a+b=b.

Takodje iz toga sledi da je bilo koje a = 0.

Ima jedna greska u svemu ovome koja objasnjava...

This post has been edited by Stefan_chemist: Dec 7 2007, 06:48 PM


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Slovenatz
post Dec 7 2007, 06:50 PM
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delio si sa a-b= 0


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pyost
post Dec 7 2007, 06:50 PM
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Deus Ex Makina
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3 minuta biggrin.gif Vidi se ko ide u D laugh.gif


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Stefan_chemist
post Dec 7 2007, 06:50 PM
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tongue.gif

Sad vi nesto...


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Hannibal Lecter
post Dec 7 2007, 06:56 PM
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U jednom selu postoji samo jedan berberin-muskarac. Svi se u selu ili briju sami ili ih brije berberin. Ko brije berberina?


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Svi me žele, a ja sam nedodirljiv!
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Stefan_chemist
post Dec 7 2007, 06:58 PM
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Pa on brije sam sebe... unsure.gif


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RZA
post Dec 7 2007, 06:59 PM
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Njeno Ljubičanstvo


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pitajne treba da glasi, gde je to mesto na zemlji.. odgovor: nema ga?? >.< unsure.gif i guess.


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Slovenatz
post Dec 7 2007, 07:06 PM
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Noddy je n00b, zadatak treba da glasi ovako:

Jedan berberin u selu. Berberin brije sve koje se ne briju sami. Ko brije berberina?

This post has been edited by Slovenatz: Dec 7 2007, 07:07 PM


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Stefan_chemist
post Dec 7 2007, 07:09 PM
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Pa ako berberin brije sam sebe, onda se on brije sam, pa ga ne brije berberin... huh.gif

A ako se berberin ne brije sam, on onda ide kod berberina na brijanje, pa ga berberin brije, pa opet dolazimo na ovo prvo... huh.gif

Nema takvog naselja XD.gif

This post has been edited by Stefan_chemist: Dec 7 2007, 07:10 PM


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username
post Dec 7 2007, 07:54 PM
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http://sr.wikipedia.org/wiki/%D0%9F%D0%B0%...%B0%D1%86%D0%B0
paradoks blizanaca ali to je fizika ne mat.
i http://en.wikipedia.org/wiki/List_of_paradoxes

This post has been edited by username: Dec 7 2007, 09:18 PM
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Hannibal Lecter
post Dec 7 2007, 11:58 PM
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tacno
inace ovo nam je sopic postavio cini mi se...


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And as we wind on down the road
Our shadows taller than our soul
There walks a lady we all know
Who shines white light and wants to show
How everything still turns to gold
And if you listen very hard
The truth will come to you at last
When all are one and one is all
To be a rock and not to roll


Svi me žele, a ja sam nedodirljiv!
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milija
post Dec 8 2007, 12:44 AM
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Ajde pricajte o Gedelovoj teoremi tongue.gif


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Hannibal Lecter
post Dec 8 2007, 01:53 AM
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Gede-sta? XD.gif


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And as we wind on down the road
Our shadows taller than our soul
There walks a lady we all know
Who shines white light and wants to show
How everything still turns to gold
And if you listen very hard
The truth will come to you at last
When all are one and one is all
To be a rock and not to roll


Svi me žele, a ja sam nedodirljiv!
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Nostradamus
post Dec 8 2007, 02:00 AM
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Gedelovih teorema nepotpunosti ima 2, na koju si mislio?


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 (a,b) \sim (c,d) \Leftrightarrow (a - c) \in \mathbb{Z}  \wedge  (b - d) \in \mathbb{Z}

\mathbb{T}^2\equiv\mathbb{R}^2/\sim
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Stefan_chemist
post Dec 8 2007, 12:24 PM
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QUOTE(Noddy)
Gede-sta? XD.gif.gif


QUOTE(Wikipedia)
Gedelova teorema o potpunosti je teorema matematičke logike koju je dokazao Kurt Gedel u svojoj doktorskoj disertaciji 1929. i kasnije u radu objavljenom 1930. U svom najpoznatijem obliku, ona tvrdi da je u predikatskom računu prvog reda svaka logički valjana formula dokaziva. Ovo je jedna od najvažnijih teorema matematičke logike, jer pokazuje da klasičan predikatski račun "sadrži" sve zakone logike koji se mogu iskazati predikatskim formulama.



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milija
post Dec 8 2007, 01:03 PM
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Fora je sto nedokaziva, a ne da mozes da je dokazes.


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Nostradamus
post Dec 8 2007, 01:10 PM
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Da, ali osim Gedelove teoreme potpunosti, imas 2 Gedelove teoreme nepotpunosti, koje manje vise kazu da ces uvek imati neka nedokaziva tvrdjenja. Npr. u teoriji skupova tvrdjenje da li postoji skup cija je kardinalnost izmedju skupova N i R se ne moze ni dokazati ni opovrgnuti

QUOTE(milija @ Dec 8 2007, 01:03 PM)
Fora je sto nedokaziva, a ne da mozes da je dokazes.
*



Na sta si mislio???

This post has been edited by Nostradamus: Dec 8 2007, 01:11 PM


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 (a,b) \sim (c,d) \Leftrightarrow (a - c) \in \mathbb{Z}  \wedge  (b - d) \in \mathbb{Z}

\mathbb{T}^2\equiv\mathbb{R}^2/\sim
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Kuzman
post Dec 10 2007, 04:13 PM
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da tvrdjenje moze biti nedokazivo, a nije moguce cak ni dokazati da je nedokazivo.


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Nostradamus
post Dec 10 2007, 04:26 PM
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Tako nesto jos nije otkriveno


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 (a,b) \sim (c,d) \Leftrightarrow (a - c) \in \mathbb{Z}  \wedge  (b - d) \in \mathbb{Z}

\mathbb{T}^2\equiv\mathbb{R}^2/\sim
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milija
post Dec 11 2007, 02:24 AM
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Zaista se nisam vise upustao u problem sa Gedelovim teoremama. Ako ti nije problem pisi vise o tome ovde.

Koliko sam ja shvatio i ono sto sam pokupio na predavanjima u Petnici (istina polubudan XD.gif) jeste da nijedan dokaz ne moze da se dokaze. Tipa valjda ono ako nam Kricanin kaze: "Svi Kricani lazu" ne mozemo da dokazemo da li on laze ili ne...


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