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nikolapfc
post Mar 8 2011, 05:59 PM
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Za pocetak,zovem se Nikola i idem u osnovnu skolu.Registrovao sam na ovaj forum,jer su mi stvarno potrebni resenja ovih zadataka iz fizike,toliko potrebni da od toga zavisi moj upis u srednju skolu,ako bilo ko zna kako da ih resi bio bih mu veoma zahvalan...Ovo su zadaci

1. odrediti jacinu homogenog elektricnog polja ako se pri pomeranju naelektrisane kuglice vrsi rad od 20J.kuglica se pomera duz linije sile za 20 cm a njeno naelektrisanje je 0,4 C.

2. pri proticanju struje kroz poprecni presek provodnika za 3 sekunde prodje kolicina naelektrisanja od 20 C.kolika ce kolicina naelektrisanja proteci za 8 sekundi?kolika je jacina struje?

3.kolika treba da bude povrsina poprecnog preseka gvozdene telefonske zice duzine 600 km da bi otpor bio 50 K oma?specificni otpor gvozdja je 12*10 na -8 om metara.

4. otpor potrosaca je 15 oma.elektromotorna sila izvora je 12 V,a unutrasnji otpor izvora je 0,5 oma.kolika je jacina struje?
nadji u svesci ili knjizi oznaku za om posto ne mogu da napisem na kompu...
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pyost
post Mar 9 2011, 12:19 AM
Post #2


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Svi ovi zadaci se svode na koriscenje po jedne formule...

1. Formula za jacinu elektricnog polja
E = \frac{F}{q} = \frac{A}{q \cdot l}
E - jacina polja
F - sila
q - kolicina naelektrisanja
A - rad
L - duzina


2. Formula za jacinu struje
user posted image
I - jacina struje
Q - kolicina naelektrisanja
T - vreme


3. Formula za otpor provodnika
user posted image
R - otpor
Ro - specifisna otpornost
L - duzina provodnika
A - poprecni presek provodnika


4. Omov zakon
I = \frac{U}{R+r}
I - jacina struje
U - elektromotorna sila izvora
R - otpor potrosaca
r - unutrasnji otpor izvora


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DSoboci
post Mar 9 2011, 01:11 AM
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Mala ispravka, gore je F=A/l, a ne A*l, pa je formula E=F/ql, inace je super
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Kuzman
post Mar 9 2011, 01:22 AM
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Nesica saves the day smile.gif


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What's cuter than a platonic solid? A cat dressed up as a platonic solid for Halloween!
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pyost
post Mar 9 2011, 08:35 AM
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QUOTE(DSoboci @ Mar 9 2011, 01:11 AM)
Mala ispravka, gore je F=A/l, a ne A*l, pa je formula E=F/ql, inace je super
*



Stvarno se sramotim, zaboravio sam formulu za rad blush.gif


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DSoboci
post Mar 9 2011, 10:48 AM
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I ja sam failovao, formula je A/ql hahahha
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Kuzman
post Mar 9 2011, 11:29 AM
Post #7





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ma Log[A*q]/Log[l] sta lozite tipa!


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What's cuter than a platonic solid? A cat dressed up as a platonic solid for Halloween!
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nikolapfc
post Mar 9 2011, 01:42 PM
Post #8





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Hvala ljudi samo mi je potrebna provera da li sam tacno izracunao..

1. zadatak resenje je: E.=250 N/C
2. zadataj resenje je: q2=53,36 C
3. zadatak resenje je: S=144*10 na -8 m kvadratnih
4.zadatak resenje je: I=1,3 A

Je l su tacni rezultati?
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pyost
post Mar 9 2011, 02:08 PM
Post #9


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Drugi i cetvrti nisu, mada si u drugom verovatno pogresio u kucanju, izracunaj ponovo.


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nikolapfc
post Mar 9 2011, 02:15 PM
Post #10





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Aha dobro,ali samo mi nije jasno gde sam pogresio u 4. zadatku?
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pyost
post Mar 9 2011, 02:20 PM
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I\ =\ \frac{U}{R+r}\ =\ \frac{12V}{15\Om\ +\ 0.5\Om}


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nikolapfc
post Mar 9 2011, 02:24 PM
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Aha sad mi je jasno,nisam lepo izracuonao..Sad dobijem rezultat veliki ali zaokruzicu na 0,774..
Je l sad dobro?
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pyost
post Mar 9 2011, 02:29 PM
Post #13


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Jeste


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nikolapfc
post Mar 9 2011, 02:35 PM
Post #14





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E druze mozes li mi samo drugi pomoci,ne znam bas najbolje ove jedinice i pretvaranje..
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pyost
post Mar 9 2011, 02:40 PM
Post #15


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Pa nista, nije 53.36 nego 53.33


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nikolapfc
post Mar 9 2011, 02:41 PM
Post #16





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Uh dobro je ja rekao odmah sta sam sad uradio..biggrin.gif
Zeleo bih da vam se zahvalim na pomoci puno ste mi pomogli..
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SBS
post Mar 9 2011, 11:23 PM
Post #17



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a šta planiraš da upišeš?


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зашто цитирати песму, кад једноставно можеш рећи своје мишљење: " Не волим кнедле са шљивама"!!!


Now i wanna sniff some glue!
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Ucenik20
post Jan 7 2012, 04:09 PM
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jel moze neko da mi pomogne da naucim programske jezike c, c++ pascal itd?
posto bih vole da se bavim programiranjem......
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dadkristy94
post Jan 7 2012, 09:48 PM
Post #19





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http://pascal-programming.info/lesson1.php
http://www.cprogramming.com/

Naravno postoji gomila sajtova na istu temu. Izguglaj i pronadji objasnjenje koje ti najvise odgovara smile.gif


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(Za ono sto je jasno dokazivanje nije potrebno) XD
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pyost
post Jan 8 2012, 12:24 AM
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Ovi linkovi koje je dadkristy ostavila su odlični za početak. Samo se nadam da znaš engleski, pošto bez toga teško da ćeš daleko dogurati.


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